1454122200035 has 4 divisors (see below), whose sum is σ = 1744946640048. Its totient is φ = 1163297760024.

The previous prime is 1454122200031. The next prime is 1454122200053. The reversal of 1454122200035 is 5300022214541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1454122200035 - 2² = 1454122200031 is a prime.

It is a super-2 number, since 2×1454122200035² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1454122199980 and 1454122200007.

It is not an unprimeable number, because it can be changed into a prime (1454122200031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 145412219999 + ... + 145412220008.

It is an arithmetic number, because the mean of its divisors is an integer number (436236660012).

Almost surely, 2^{1454122200035} is an apocalyptic number.

1454122200035 is a deficient number, since it is larger than the sum of its proper divisors (290824440013).

1454122200035 is an equidigital number, since it uses as much as digits as its factorization.

1454122200035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 290824440012.

The product of its (nonzero) digits is 9600, while the sum is 29.

Adding to 1454122200035 its reverse (5300022214541), we get a palindrome (6754144414576).

The spelling of 1454122200035 in words is "one trillion, four hundred fifty-four billion, one hundred twenty-two million, two hundred thousand, thirty-five".