Search a number
-
+
1454123431142 = 2727061715571
BaseRepresentation
bin10101001010010000100…
…000101011010011100110
312011000100100202222020122
4111022100200223103212
5142311021044244032
63032003131401542
7210025351140644
oct25122040532346
95130310688218
101454123431142
1151076584a178
121b599abb32b2
13a717aa23b85
1450546820194
1527c59a0c012
hex1529082b4e6

1454123431142 has 4 divisors (see below), whose sum is σ = 2181185146716. Its totient is φ = 727061715570.

The previous prime is 1454123431093. The next prime is 1454123431151. The reversal of 1454123431142 is 2411343214541.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×14541234311422 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 363530857784 + ... + 363530857787.

It is an arithmetic number, because the mean of its divisors is an integer number (545296286679).

Almost surely, 21454123431142 is an apocalyptic number.

1454123431142 is a deficient number, since it is larger than the sum of its proper divisors (727061715574).

1454123431142 is an equidigital number, since it uses as much as digits as its factorization.

1454123431142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 727061715573.

The product of its digits is 46080, while the sum is 35.

Adding to 1454123431142 its reverse (2411343214541), we get a palindrome (3865466645683).

The spelling of 1454123431142 in words is "one trillion, four hundred fifty-four billion, one hundred twenty-three million, four hundred thirty-one thousand, one hundred forty-two".

Divisors: 1 2 727061715571 1454123431142