1454330341141 has 4 divisors (see below), whose sum is σ = 1478980008000. Its totient is φ = 1429680674284.

The previous prime is 1454330341063. The next prime is 1454330341231. The reversal of 1454330341141 is 1411430334541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1454330341141 - 2²⁹ = 1453793470229 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1454330341097 and 1454330341106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1454330311141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12324833341 + ... + 12324833458.

It is an arithmetic number, because the mean of its divisors is an integer number (369745002000).

Almost surely, 2^{1454330341141} is an apocalyptic number.

It is an amenable number.

1454330341141 is a deficient number, since it is larger than the sum of its proper divisors (24649666859).

1454330341141 is an equidigital number, since it uses as much as digits as its factorization.

1454330341141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24649666858.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 1454330341141 its reverse (1411430334541), we get a palindrome (2865760675682).

The spelling of 1454330341141 in words is "one trillion, four hundred fifty-four billion, three hundred thirty million, three hundred forty-one thousand, one hundred forty-one".