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1455138315541 is a prime number
BaseRepresentation
bin10101001011001101000…
…000001001110100010101
312011002222002110102220201
4111023031000021310111
5142320110402044131
63032251544100501
7210062453413411
oct25131500116425
95132862412821
101455138315541
11511136709909
121b6022a64731
13a72b0072ba1
1450601523d41
1527cb8b7d761
hex152cd009d15

1455138315541 has 2 divisors, whose sum is σ = 1455138315542. Its totient is φ = 1455138315540.

The previous prime is 1455138315523. The next prime is 1455138315577.

1455138315541 is nontrivially palindromic in base 10.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1350499652100 + 104638663441 = 1162110^2 + 323479^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 1455138315541 - 213 = 1455138307349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1455138315491 and 1455138315500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1455138315511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727569157770 + 727569157771.

It is an arithmetic number, because the mean of its divisors is an integer number (727569157771).

Almost surely, 21455138315541 is an apocalyptic number.

It is an amenable number.

1455138315541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1455138315541 is an equidigital number, since it uses as much as digits as its factorization.

1455138315541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720000, while the sum is 46.

The spelling of 1455138315541 in words is "one trillion, four hundred fifty-five billion, one hundred thirty-eight million, three hundred fifteen thousand, five hundred forty-one".