Base | Representation |
---|---|
bin | 1000011110000110110… |
… | …0011001000011011001 |
3 | 111220121120100211212111 |
4 | 2013201230121003121 |
5 | 4341011212300241 |
6 | 150503503512321 |
7 | 13341063154156 |
oct | 2074154310331 |
9 | 456546324774 |
10 | 145520431321 |
11 | 56795542981 |
12 | 242525b86a1 |
13 | 109514aa4c5 |
14 | 708688322d |
15 | 3bba6c9c81 |
hex | 21e1b190d9 |
145520431321 has 2 divisors, whose sum is σ = 145520431322. Its totient is φ = 145520431320.
The previous prime is 145520431319. The next prime is 145520431393. The reversal of 145520431321 is 123134025541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 131795137296 + 13725294025 = 363036^2 + 117155^2 .
It is a cyclic number.
It is not a de Polignac number, because 145520431321 - 21 = 145520431319 is a prime.
Together with 145520431319, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (145520431921) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72760215660 + 72760215661.
It is an arithmetic number, because the mean of its divisors is an integer number (72760215661).
Almost surely, 2145520431321 is an apocalyptic number.
It is an amenable number.
145520431321 is a deficient number, since it is larger than the sum of its proper divisors (1).
145520431321 is an equidigital number, since it uses as much as digits as its factorization.
145520431321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 145520431321 its reverse (123134025541), we get a palindrome (268654456862).
The spelling of 145520431321 in words is "one hundred forty-five billion, five hundred twenty million, four hundred thirty-one thousand, three hundred twenty-one".
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