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145520541410455 = 529104108282091
BaseRepresentation
bin100001000101100110100100…
…001011011010010010010111
3201002020121221201212011000201
4201011212210023122102113
5123033202032100113310
61233255114104321331
742436340450032621
oct4105464413322227
9632217851764021
10145520541410455
1142404a07a05982
12143a2a32a73247
1363276b3520c73
1427d1336033c11
1511c54cada4e3a
hex8459a42da497

145520541410455 has 4 divisors (see below), whose sum is σ = 174624649692552. Its totient is φ = 116416433128360.

The previous prime is 145520541410449. The next prime is 145520541410467. The reversal of 145520541410455 is 554014145025541.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-145520541410455 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14552054141041 + ... + 14552054141050.

It is an arithmetic number, because the mean of its divisors is an integer number (43656162423138).

Almost surely, 2145520541410455 is an apocalyptic number.

145520541410455 is a deficient number, since it is larger than the sum of its proper divisors (29104108282097).

145520541410455 is an equidigital number, since it uses as much as digits as its factorization.

145520541410455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29104108282096.

The product of its (nonzero) digits is 1600000, while the sum is 46.

Adding to 145520541410455 its reverse (554014145025541), we get a palindrome (699534686435996).

The spelling of 145520541410455 in words is "one hundred forty-five trillion, five hundred twenty billion, five hundred forty-one million, four hundred ten thousand, four hundred fifty-five".

Divisors: 1 5 29104108282091 145520541410455