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14552421253 is a prime number
BaseRepresentation
bin11011000110110010…
…00101001110000101
31101120011221121001221
431203121011032011
5214300404440003
610404004520341
71023423353056
oct154331051605
941504847057
1014552421253
11619850a527
1229a16b00b1
1314abbb9466
149c09d672d
155a28a37bd
hex363645385

14552421253 has 2 divisors, whose sum is σ = 14552421254. Its totient is φ = 14552421252.

The previous prime is 14552421203. The next prime is 14552421307. The reversal of 14552421253 is 35212425541.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7436992644 + 7115428609 = 86238^2 + 84353^2 .

It is an emirp because it is prime and its reverse (35212425541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14552421253 - 213 = 14552413061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14552421203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7276210626 + 7276210627.

It is an arithmetic number, because the mean of its divisors is an integer number (7276210627).

Almost surely, 214552421253 is an apocalyptic number.

It is an amenable number.

14552421253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14552421253 is an equidigital number, since it uses as much as digits as its factorization.

14552421253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48000, while the sum is 34.

Adding to 14552421253 its reverse (35212425541), we get a palindrome (49764846794).

The spelling of 14552421253 in words is "fourteen billion, five hundred fifty-two million, four hundred twenty-one thousand, two hundred fifty-three".