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14559426941 is a prime number
BaseRepresentation
bin11011000111100111…
…10011100101111101
31101120200010112001212
431203303303211331
5214304203130231
610404415014205
71023540041603
oct154363634575
941520115055
1014559426941
1161a1464a54
1229a3b0a365
1314b04a0137
149c18db873
155a32d942b
hex363cf397d

14559426941 has 2 divisors, whose sum is σ = 14559426942. Its totient is φ = 14559426940.

The previous prime is 14559426907. The next prime is 14559426953. The reversal of 14559426941 is 14962495541.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13941705625 + 617721316 = 118075^2 + 24854^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14559426941 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14559426941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14559426341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7279713470 + 7279713471.

It is an arithmetic number, because the mean of its divisors is an integer number (7279713471).

Almost surely, 214559426941 is an apocalyptic number.

It is an amenable number.

14559426941 is a deficient number, since it is larger than the sum of its proper divisors (1).

14559426941 is an equidigital number, since it uses as much as digits as its factorization.

14559426941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1555200, while the sum is 50.

The spelling of 14559426941 in words is "fourteen billion, five hundred fifty-nine million, four hundred twenty-six thousand, nine hundred forty-one".