Base | Representation |
---|---|
bin | 1000011110011111010… |
… | …0001011001111110111 |
3 | 111220212201121202010201 |
4 | 2013213310023033313 |
5 | 4341214010311343 |
6 | 150522013101331 |
7 | 13343451140356 |
oct | 2074764131767 |
9 | 456781552121 |
10 | 145623135223 |
11 | 56838510935 |
12 | 24280a87847 |
13 | 10969859947 |
14 | 709637999d |
15 | 3bc471594d |
hex | 21e7d0b3f7 |
145623135223 has 2 divisors, whose sum is σ = 145623135224. Its totient is φ = 145623135222.
The previous prime is 145623135199. The next prime is 145623135227. The reversal of 145623135223 is 322531326541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145623135223 - 233 = 137033200631 is a prime.
It is a super-2 number, since 2×1456231352232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145623135227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72811567611 + 72811567612.
It is an arithmetic number, because the mean of its divisors is an integer number (72811567612).
Almost surely, 2145623135223 is an apocalyptic number.
145623135223 is a deficient number, since it is larger than the sum of its proper divisors (1).
145623135223 is an equidigital number, since it uses as much as digits as its factorization.
145623135223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 129600, while the sum is 37.
The spelling of 145623135223 in words is "one hundred forty-five billion, six hundred twenty-three million, one hundred thirty-five thousand, two hundred twenty-three".
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