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1460028731597 is a prime number
BaseRepresentation
bin10101001111110000011…
…111100111000011001101
312011120120220122022120022
4111033300133213003031
5142410114323402342
63034421122431525
7210324605311232
oct25176037470315
95146526568508
101460028731597
11513216179877
121b6b688025a5
13a78ac2b38b7
1450946c1b789
1527ea318a9d2
hex153f07e70cd

1460028731597 has 2 divisors, whose sum is σ = 1460028731598. Its totient is φ = 1460028731596.

The previous prime is 1460028731537. The next prime is 1460028731617. The reversal of 1460028731597 is 7951378200641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1439109737641 + 20918993956 = 1199629^2 + 144634^2 .

It is a cyclic number.

It is not a de Polignac number, because 1460028731597 - 212 = 1460028727501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1460028731537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 730014365798 + 730014365799.

It is an arithmetic number, because the mean of its divisors is an integer number (730014365799).

It is a 1-persistent number, because it is pandigital, but 2⋅1460028731597 = 2920057463194 is not.

Almost surely, 21460028731597 is an apocalyptic number.

It is an amenable number.

1460028731597 is a deficient number, since it is larger than the sum of its proper divisors (1).

1460028731597 is an equidigital number, since it uses as much as digits as its factorization.

1460028731597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 53.

The spelling of 1460028731597 in words is "one trillion, four hundred sixty billion, twenty-eight million, seven hundred thirty-one thousand, five hundred ninety-seven".