Base | Representation |
---|---|
bin | 11011001100101000… |
… | …01000011000011111 |
3 | 1101200121012202220122 |
4 | 31212110020120133 |
5 | 214400433031020 |
6 | 10412515505155 |
7 | 1024560215021 |
oct | 154624103037 |
9 | 41617182818 |
10 | 14601455135 |
11 | 62131603a3 |
12 | 29b5bb81bb |
13 | 14b90c6ba7 |
14 | 9c731c011 |
15 | 5a6d3c125 |
hex | 36650861f |
14601455135 has 4 divisors (see below), whose sum is σ = 17521746168. Its totient is φ = 11681164104.
The previous prime is 14601455129. The next prime is 14601455147. The reversal of 14601455135 is 53155410641.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14601455135 - 210 = 14601454111 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14601455095 and 14601455104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1460145509 + ... + 1460145518.
It is an arithmetic number, because the mean of its divisors is an integer number (4380436542).
Almost surely, 214601455135 is an apocalyptic number.
14601455135 is a deficient number, since it is larger than the sum of its proper divisors (2920291033).
14601455135 is an equidigital number, since it uses as much as digits as its factorization.
14601455135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2920291032.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 14601455135 its reverse (53155410641), we get a palindrome (67756865776).
The spelling of 14601455135 in words is "fourteen billion, six hundred one million, four hundred fifty-five thousand, one hundred thirty-five".
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