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146161731300 = 22352131719294001
BaseRepresentation
bin1000100000011111101…
…0110000011011100100
3111222021021002021001120
42020013322300123210
54343314400400200
6151051253053540
713363011134334
oct2100772603344
9458237067046
10146161731300
1156a9453a062
12243b13272b0
1310a24306550
147107adb0c4
153c06b549a0
hex2207eb06e4

146161731300 has 576 divisors, whose sum is σ = 525228883200. Its totient is φ = 30965760000.

The previous prime is 146161731299. The next prime is 146161731301. The reversal of 146161731300 is 3137161641.

146161731300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (146161731299) and next prime (146161731301).

It is a super-2 number, since 2×1461617313002 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (146161731301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 36529300 + ... + 36533300.

It is an arithmetic number, because the mean of its divisors is an integer number (911855700).

Almost surely, 2146161731300 is an apocalyptic number.

146161731300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 146161731300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (262614441600).

146161731300 is an abundant number, since it is smaller than the sum of its proper divisors (379067151900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

146161731300 is a wasteful number, since it uses less digits than its factorization.

146161731300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4096 (or 4089 counting only the distinct ones).

The product of its (nonzero) digits is 9072, while the sum is 33.

Adding to 146161731300 its reverse (3137161641), we get a palindrome (149298892941).

The spelling of 146161731300 in words is "one hundred forty-six billion, one hundred sixty-one million, seven hundred thirty-one thousand, three hundred".