Base | Representation |
---|---|
bin | 10101010100011010110… |
… | …110100101100001111010 |
3 | 12012001111202121211202220 |
4 | 111110122312211201322 |
5 | 143000342244140200 |
6 | 3041005534504510 |
7 | 210562626430614 |
oct | 25243266454172 |
9 | 5161452554686 |
10 | 1465034365050 |
11 | 515354784323 |
12 | 1b7b25065136 |
13 | a81c9365699 |
14 | 50c9d947db4 |
15 | 281978564a0 |
hex | 1551ada587a |
1465034365050 has 24 divisors (see below), whose sum is σ = 3633285225696. Its totient is φ = 390675830640.
The previous prime is 1465034365019. The next prime is 1465034365057. The reversal of 1465034365050 is 505634305641.
It is a super-3 number, since 3×14650343650503 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1465034364993 and 1465034365011.
It is not an unprimeable number, because it can be changed into a prime (1465034365057) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4883447734 + ... + 4883448033.
It is an arithmetic number, because the mean of its divisors is an integer number (151386884404).
Almost surely, 21465034365050 is an apocalyptic number.
1465034365050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1465034365050 is an abundant number, since it is smaller than the sum of its proper divisors (2168250860646).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1465034365050 is a wasteful number, since it uses less digits than its factorization.
1465034365050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9766895782 (or 9766895777 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 42.
The spelling of 1465034365050 in words is "one trillion, four hundred sixty-five billion, thirty-four million, three hundred sixty-five thousand, fifty".
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