Base | Representation |
---|---|
bin | 100001010100011100000001… |
… | …010101011101101100000011 |
3 | 201012212002101100211110121122 |
4 | 201110130001111131230003 |
5 | 123201402420430413232 |
6 | 1235355315120142455 |
7 | 42603111044333114 |
oct | 4124340125355403 |
9 | 635762340743548 |
10 | 146540011576067 |
11 | 427682a727642a |
12 | 14528529467a2b |
13 | 639c882494855 |
14 | 282880824220b |
15 | 11e1c96ac9312 |
hex | 85470155db03 |
146540011576067 has 2 divisors, whose sum is σ = 146540011576068. Its totient is φ = 146540011576066.
The previous prime is 146540011576039. The next prime is 146540011576069. The reversal of 146540011576067 is 760675110045641.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 146540011576067 - 212 = 146540011571971 is a prime.
Together with 146540011576069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (146540011576069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73270005788033 + 73270005788034.
It is an arithmetic number, because the mean of its divisors is an integer number (73270005788034).
Almost surely, 2146540011576067 is an apocalyptic number.
146540011576067 is a deficient number, since it is larger than the sum of its proper divisors (1).
146540011576067 is an equidigital number, since it uses as much as digits as its factorization.
146540011576067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4233600, while the sum is 53.
The spelling of 146540011576067 in words is "one hundred forty-six trillion, five hundred forty billion, eleven million, five hundred seventy-six thousand, sixty-seven".
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