Base | Representation |
---|---|
bin | 10101010101011011001… |
… | …010100100011110011111 |
3 | 12012011021221220201121112 |
4 | 111111123022210132133 |
5 | 143010100004023224 |
6 | 3041305001052235 |
7 | 210631440550211 |
oct | 25253312443637 |
9 | 5164257821545 |
10 | 1466113345439 |
11 | 515858842256 |
12 | 1b818648707b |
13 | a833ba66b12 |
14 | 50d62d745b1 |
15 | 2820c43930e |
hex | 1555b2a479f |
1466113345439 has 2 divisors, whose sum is σ = 1466113345440. Its totient is φ = 1466113345438.
The previous prime is 1466113345399. The next prime is 1466113345451. The reversal of 1466113345439 is 9345433116641.
It is a strong prime.
It is an emirp because it is prime and its reverse (9345433116641) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1466113345439 - 220 = 1466112296863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1466113342439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 733056672719 + 733056672720.
It is an arithmetic number, because the mean of its divisors is an integer number (733056672720).
Almost surely, 21466113345439 is an apocalyptic number.
1466113345439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1466113345439 is an equidigital number, since it uses as much as digits as its factorization.
1466113345439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2799360, while the sum is 50.
The spelling of 1466113345439 in words is "one trillion, four hundred sixty-six billion, one hundred thirteen million, three hundred forty-five thousand, four hundred thirty-nine".
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