Search a number
-
+
1474113 = 3491371
BaseRepresentation
bin101100111111001000001
32202220002210
411213321001
5334132423
651332333
715346464
oct5477101
92686083
101474113
11917583
125b10a9
133c7c74
142a52db
151e1b93
hex167e41

1474113 has 4 divisors (see below), whose sum is σ = 1965488. Its totient is φ = 982740.

The previous prime is 1474103. The next prime is 1474127. The reversal of 1474113 is 3114741.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1474113 - 24 = 1474097 is a prime.

It is a D-number.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1474113.

It is not an unprimeable number, because it can be changed into a prime (1474103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245683 + ... + 245688.

It is an arithmetic number, because the mean of its divisors is an integer number (491372).

21474113 is an apocalyptic number.

It is an amenable number.

1474113 is a deficient number, since it is larger than the sum of its proper divisors (491375).

1474113 is an equidigital number, since it uses as much as digits as its factorization.

1474113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491374.

The product of its digits is 336, while the sum is 21.

The square root of 1474113 is about 1214.1305531120. The cubic root of 1474113 is about 113.8090833421.

Adding to 1474113 its reverse (3114741), we get a palindrome (4588854).

The spelling of 1474113 in words is "one million, four hundred seventy-four thousand, one hundred thirteen".

Divisors: 1 3 491371 1474113