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147605890253 is a prime number
BaseRepresentation
bin1000100101110111111…
…1110010010011001101
3112002222220112010201012
42021131333302103031
54404244101442003
6151450442255005
713443545236313
oct2113577622315
9462886463635
10147605890253
115766574a058
1224734ab7465
1310bc4576883
1472038260b3
153c8d81d8d8
hex225dff24cd

147605890253 has 2 divisors, whose sum is σ = 147605890254. Its totient is φ = 147605890252.

The previous prime is 147605890217. The next prime is 147605890331. The reversal of 147605890253 is 352098506741.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 146783233129 + 822657124 = 383123^2 + 28682^2 .

It is a cyclic number.

It is not a de Polignac number, because 147605890253 - 210 = 147605889229 is a prime.

It is a super-3 number, since 3×1476058902533 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (147605890753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73802945126 + 73802945127.

It is an arithmetic number, because the mean of its divisors is an integer number (73802945127).

It is a 1-persistent number, because it is pandigital, but 2⋅147605890253 = 295211780506 is not.

Almost surely, 2147605890253 is an apocalyptic number.

It is an amenable number.

147605890253 is a deficient number, since it is larger than the sum of its proper divisors (1).

147605890253 is an equidigital number, since it uses as much as digits as its factorization.

147605890253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 50.

The spelling of 147605890253 in words is "one hundred forty-seven billion, six hundred five million, eight hundred ninety thousand, two hundred fifty-three".