148055100493 has 4 divisors (see below), whose sum is σ = 148071769120. Its totient is φ = 148038431868.

The previous prime is 148055100481. The next prime is 148055100499. The reversal of 148055100493 is 394001550841.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 148055100493 - 2⁵ = 148055100461 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (148055100499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8320983 + ... + 8338756.

It is an arithmetic number, because the mean of its divisors is an integer number (37017942280).

Almost surely, 2^148055100493 is an apocalyptic number.

It is an amenable number.

148055100493 is a deficient number, since it is larger than the sum of its proper divisors (16668627).

148055100493 is an equidigital number, since it uses as much as digits as its factorization.

148055100493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16668626.

The product of its (nonzero) digits is 86400, while the sum is 40.

The spelling of 148055100493 in words is "one hundred forty-eight billion, fifty-five million, one hundred thousand, four hundred ninety-three".