Base | Representation |
---|---|
bin | 11011110010101010… |
… | …01100010001111111 |
3 | 1102111211112221200010 |
4 | 31321111030101333 |
5 | 221024122002401 |
6 | 10504314034303 |
7 | 1035513106011 |
oct | 157125142177 |
9 | 42454487603 |
10 | 14920500351 |
11 | 6367262829 |
12 | 2a84a18993 |
13 | 153a232643 |
14 | a1784c1b1 |
15 | 5c4d5ded6 |
hex | 37954c47f |
14920500351 has 4 divisors (see below), whose sum is σ = 19894000472. Its totient is φ = 9947000232.
The previous prime is 14920500251. The next prime is 14920500359. The reversal of 14920500351 is 15300502941.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14920500351 - 214 = 14920483967 is a prime.
It is a super-2 number, since 2×149205003512 (a number of 21 digits) contains 22 as substring.
It is the 122150-th Hogben number.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14920500359) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2486750056 + ... + 2486750061.
It is an arithmetic number, because the mean of its divisors is an integer number (4973500118).
Almost surely, 214920500351 is an apocalyptic number.
14920500351 is a deficient number, since it is larger than the sum of its proper divisors (4973500121).
14920500351 is an equidigital number, since it uses as much as digits as its factorization.
14920500351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4973500120.
The product of its (nonzero) digits is 5400, while the sum is 30.
The spelling of 14920500351 in words is "fourteen billion, nine hundred twenty million, five hundred thousand, three hundred fifty-one".
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