Base | Representation |
---|---|
bin | 1000101011111111011… |
… | …1000100000111111101 |
3 | 112021020100000022212011 |
4 | 2022333313010013331 |
5 | 4421124412134013 |
6 | 152321413411221 |
7 | 13532333060116 |
oct | 2127767040775 |
9 | 467210008764 |
10 | 149247771133 |
11 | 583285264aa |
12 | 24b12939b11 |
13 | 110c6784316 |
14 | 731b8dd20d |
15 | 3d37a41c3d |
hex | 22bfdc41fd |
149247771133 has 2 divisors, whose sum is σ = 149247771134. Its totient is φ = 149247771132.
The previous prime is 149247771119. The next prime is 149247771191. The reversal of 149247771133 is 331177742941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 138966419524 + 10281351609 = 372782^2 + 101397^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-149247771133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (149247771833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74623885566 + 74623885567.
It is an arithmetic number, because the mean of its divisors is an integer number (74623885567).
Almost surely, 2149247771133 is an apocalyptic number.
It is an amenable number.
149247771133 is a deficient number, since it is larger than the sum of its proper divisors (1).
149247771133 is an equidigital number, since it uses as much as digits as its factorization.
149247771133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 889056, while the sum is 49.
The spelling of 149247771133 in words is "one hundred forty-nine billion, two hundred forty-seven million, seven hundred seventy-one thousand, one hundred thirty-three".
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