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14947268343280 = 24572132910114267
BaseRepresentation
bin1101100110000010111010…
…0111101011010111110000
31221220221111211102200001121
43121200232213223113300
53424344001143441110
651442402535112024
73101622146412100
oct331405647532760
957827454380047
1014947268343280
11484311233a399
121814a69b12614
138456a1561240
14399647471200
151adc2d084cda
hexd982e9eb5f0

14947268343280 has 240 divisors, whose sum is σ = 45037217121120. Its totient is φ = 4567440697344.

The previous prime is 14947268343263. The next prime is 14947268343311. The reversal of 14947268343280 is 8234386274941.

It is a super-3 number, since 3×149472683432803 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3579294 + ... + 6534973.

It is an arithmetic number, because the mean of its divisors is an integer number (187655071338).

Almost surely, 214947268343280 is an apocalyptic number.

14947268343280 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14947268343280 is an abundant number, since it is smaller than the sum of its proper divisors (30089948777840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14947268343280 is a wasteful number, since it uses less digits than its factorization.

14947268343280 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10114336 (or 10114323 counting only the distinct ones).

The product of its (nonzero) digits is 55738368, while the sum is 61.

The spelling of 14947268343280 in words is "fourteen trillion, nine hundred forty-seven billion, two hundred sixty-eight million, three hundred forty-three thousand, two hundred eighty".