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149555328000 = 2103531329959
BaseRepresentation
bin1000101101001000110…
…0010011010000000000
3112022000202201211120020
42023102030103100000
54422242130444000
6152412121413440
713543056212301
oct2132214232000
9468022654506
10149555328000
11584760a1531
1224b9993a280
13111453c9930
14734a6bc7a8
153d54a44ba0
hex22d2313400

149555328000 has 352 divisors, whose sum is σ = 535762456320. Its totient is φ = 36812390400.

The previous prime is 149555327993. The next prime is 149555328011. The reversal of 149555328000 is 823555941.

It is a super-2 number, since 2×1495553280002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4977021 + ... + 5006979.

Almost surely, 2149555328000 is an apocalyptic number.

149555328000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 149555328000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (267881228160).

149555328000 is an abundant number, since it is smaller than the sum of its proper divisors (386207128320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

149555328000 is a wasteful number, since it uses less digits than its factorization.

149555328000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30010 (or 29982 counting only the distinct ones).

The product of its (nonzero) digits is 216000, while the sum is 42.

The spelling of 149555328000 in words is "one hundred forty-nine billion, five hundred fifty-five million, three hundred twenty-eight thousand".