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14960555551321 is a prime number
BaseRepresentation
bin1101100110110100011010…
…0110010110101001011001
31221222012210211122202212221
43121231012212112221121
53430103204210120241
651452441230104041
73102602341001002
oct331550646265131
957865724582787
1014960555551321
114848810651466
12181755794b021
13846a0b2a2413
1439a1480001a9
151ae25981a5d1
hexd9b46996a59

14960555551321 has 2 divisors, whose sum is σ = 14960555551322. Its totient is φ = 14960555551320.

The previous prime is 14960555551241. The next prime is 14960555551373. The reversal of 14960555551321 is 12315555506941.

It is an a-pointer prime, because the next prime (14960555551373) can be obtained adding 14960555551321 to its sum of digits (52).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14613310525696 + 347245025625 = 3822736^2 + 589275^2 .

It is a cyclic number.

It is not a de Polignac number, because 14960555551321 - 221 = 14960553454169 is a prime.

It is not a weakly prime, because it can be changed into another prime (14960555551421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7480277775660 + 7480277775661.

It is an arithmetic number, because the mean of its divisors is an integer number (7480277775661).

Almost surely, 214960555551321 is an apocalyptic number.

It is an amenable number.

14960555551321 is a deficient number, since it is larger than the sum of its proper divisors (1).

14960555551321 is an equidigital number, since it uses as much as digits as its factorization.

14960555551321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4050000, while the sum is 52.

The spelling of 14960555551321 in words is "fourteen trillion, nine hundred sixty billion, five hundred fifty-five million, five hundred fifty-one thousand, three hundred twenty-one".