Base | Representation |
---|---|
bin | 1101101000001111011010… |
… | …1101010101001011000111 |
3 | 1222001112212100222200201222 |
4 | 3122003312231111023013 |
5 | 3431003222130204131 |
6 | 51512001310110555 |
7 | 3104425616643152 |
oct | 332036655251307 |
9 | 58045770880658 |
10 | 14984985006791 |
11 | 4858107418988 |
12 | 18202351ab45b |
13 | 849102554207 |
14 | 39b3c46aac99 |
15 | 1aebd938c87b |
hex | da0f6b552c7 |
14984985006791 has 2 divisors, whose sum is σ = 14984985006792. Its totient is φ = 14984985006790.
The previous prime is 14984985006779. The next prime is 14984985006793. The reversal of 14984985006791 is 19760058948941.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14984985006791 - 226 = 14984917897927 is a prime.
It is a super-2 number, since 2×149849850067912 (a number of 27 digits) contains 22 as substring.
Together with 14984985006793, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14984985006793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7492492503395 + 7492492503396.
It is an arithmetic number, because the mean of its divisors is an integer number (7492492503396).
Almost surely, 214984985006791 is an apocalyptic number.
14984985006791 is a deficient number, since it is larger than the sum of its proper divisors (1).
14984985006791 is an equidigital number, since it uses as much as digits as its factorization.
14984985006791 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 156764160, while the sum is 71.
The spelling of 14984985006791 in words is "fourteen trillion, nine hundred eighty-four billion, nine hundred eighty-five million, six thousand, seven hundred ninety-one".
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