1500041 has 2 divisors, whose sum is σ = 1500042. Its totient is φ = 1500040.

The previous prime is 1500019. The next prime is 1500043. The reversal of 1500041 is 1400051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 802816 + 697225 = 896^2 + 835^2 .

It is an emirp because it is prime and its reverse (1400051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1500041 - 2⁶ = 1499977 is a prime.

Together with 1500043, it forms a pair of twin primes.

It is a Chen prime.

1500041 is a modest number, since divided by 41 gives 15 as remainder.

It is a junction number, because it is equal to n+sod(n) for n = 1499995 and 1500031.

It is not a weakly prime, because it can be changed into another prime (1500043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a good prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750020 + 750021.

It is an arithmetic number, because the mean of its divisors is an integer number (750021).

2^1500041 is an apocalyptic number.

It is an amenable number.

1500041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1500041 is an equidigital number, since it uses as much as digits as its factorization.

1500041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20, while the sum is 11.

The square root of 1500041 is about 1224.7616094571. The cubic root of 1500041 is about 114.4724672077.

Adding to 1500041 its reverse (1400051), we get a palindrome (2900092).

The spelling of 1500041 in words is "one million, five hundred thousand, forty-one".