150004465361113 has 4 divisors (see below), whose sum is σ = 163641234939408. Its totient is φ = 136367695782820.

The previous prime is 150004465361081. The next prime is 150004465361129. The reversal of 150004465361113 is 311163564400051.

It is a happy number.

150004465361113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150004465361113 - 2⁵ = 150004465361081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150004465361143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6818384789131 + ... + 6818384789152.

It is an arithmetic number, because the mean of its divisors is an integer number (40910308734852).

Almost surely, 2^{150004465361113} is an apocalyptic number.

It is an amenable number.

150004465361113 is a deficient number, since it is larger than the sum of its proper divisors (13636769578295).

150004465361113 is a wasteful number, since it uses less digits than its factorization.

150004465361113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13636769578294.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 150004465361113 in words is "one hundred fifty trillion, four billion, four hundred sixty-five million, three hundred sixty-one thousand, one hundred thirteen".