Base | Representation |
---|---|
bin | 1000101110110110001… |
… | …0111000111110111011 |
3 | 112100012202020201000022 |
4 | 2023231202320332323 |
5 | 4424212121001210 |
6 | 152525433401055 |
7 | 13560330645263 |
oct | 2135542707673 |
9 | 470182221008 |
10 | 150014234555 |
11 | 58691140849 |
12 | 250a756918b |
13 | 111b94c4583 |
14 | 73916187a3 |
15 | 3d7ee92155 |
hex | 22ed8b8fbb |
150014234555 has 12 divisors (see below), whose sum is σ = 183119953872. Its totient is φ = 117977282640.
The previous prime is 150014234479. The next prime is 150014234569. The reversal of 150014234555 is 555432410051.
It is not a de Polignac number, because 150014234555 - 212 = 150014230459 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4292111 + ... + 4326920.
It is an arithmetic number, because the mean of its divisors is an integer number (15259996156).
Almost surely, 2150014234555 is an apocalyptic number.
150014234555 is a deficient number, since it is larger than the sum of its proper divisors (33105719317).
150014234555 is an frugal number, since it uses more digits than its factorization.
150014234555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8619154 (or 8619095 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 35.
The spelling of 150014234555 in words is "one hundred fifty billion, fourteen million, two hundred thirty-four thousand, five hundred fifty-five".
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