Base | Representation |
---|---|
bin | 10101110101001100001… |
… | …010100011100110111101 |
3 | 12022102100000021112121212 |
4 | 111311030022203212331 |
5 | 144034423141001023 |
6 | 3105105303334205 |
7 | 213246612453536 |
oct | 25651412434675 |
9 | 5272300245555 |
10 | 1500221422013 |
11 | 529270977a96 |
12 | 202905151365 |
13 | ab616261352 |
14 | 5287ac2768d |
15 | 29056a35e78 |
hex | 15d4c2a39bd |
1500221422013 has 2 divisors, whose sum is σ = 1500221422014. Its totient is φ = 1500221422012.
The previous prime is 1500221421961. The next prime is 1500221422039. The reversal of 1500221422013 is 3102241220051.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1236628513444 + 263592908569 = 1112038^2 + 513413^2 .
It is a cyclic number.
It is not a de Polignac number, because 1500221422013 - 234 = 1483041552829 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1500221422013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1500221122013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750110711006 + 750110711007.
It is an arithmetic number, because the mean of its divisors is an integer number (750110711007).
Almost surely, 21500221422013 is an apocalyptic number.
It is an amenable number.
1500221422013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1500221422013 is an equidigital number, since it uses as much as digits as its factorization.
1500221422013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 1500221422013 its reverse (3102241220051), we get a palindrome (4602462642064).
The spelling of 1500221422013 in words is "one trillion, five hundred billion, two hundred twenty-one million, four hundred twenty-two thousand, thirteen".
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