150040138117 has 2 divisors, whose sum is σ = 150040138118. Its totient is φ = 150040138116.

The previous prime is 150040138009. The next prime is 150040138121. The reversal of 150040138117 is 711831040051.

It is a happy number.

150040138117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 149656017316 + 384120801 = 386854^2 + 19599^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-150040138117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150040138817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75020069058 + 75020069059.

It is an arithmetic number, because the mean of its divisors is an integer number (75020069059).

Almost surely, 2^150040138117 is an apocalyptic number.

It is an amenable number.

150040138117 is a deficient number, since it is larger than the sum of its proper divisors (1).

150040138117 is an equidigital number, since it uses as much as digits as its factorization.

150040138117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3360, while the sum is 31.

Adding to 150040138117 its reverse (711831040051), we get a palindrome (861871178168).

The spelling of 150040138117 in words is "one hundred fifty billion, forty million, one hundred thirty-eight thousand, one hundred seventeen".