Base | Representation |
---|---|
bin | 1000101110111100101… |
… | …0011100000100110101 |
3 | 112100021122022210100202 |
4 | 2023233022130010311 |
5 | 4424241043113000 |
6 | 152532243250245 |
7 | 13561110452051 |
oct | 2135712340465 |
9 | 470248283322 |
10 | 150041379125 |
11 | 586a54a0980 |
12 | 250b4679985 |
13 | 111c2009951 |
14 | 7395082c61 |
15 | 3d82554dd5 |
hex | 22ef29c135 |
150041379125 has 16 divisors (see below), whose sum is σ = 204274519488. Its totient is φ = 109121002000.
The previous prime is 150041379119. The next prime is 150041379139. The reversal of 150041379125 is 521973140051.
150041379125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 150041379125 - 214 = 150041362741 is a prime.
It is a super-3 number, since 3×1500413791253 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54559127 + ... + 54561876.
It is an arithmetic number, because the mean of its divisors is an integer number (12767157468).
Almost surely, 2150041379125 is an apocalyptic number.
It is an amenable number.
150041379125 is a deficient number, since it is larger than the sum of its proper divisors (54233140363).
150041379125 is a wasteful number, since it uses less digits than its factorization.
150041379125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109121029 (or 109121019 counting only the distinct ones).
The product of its (nonzero) digits is 37800, while the sum is 38.
The spelling of 150041379125 in words is "one hundred fifty billion, forty-one million, three hundred seventy-nine thousand, one hundred twenty-five".
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