15004152053 has 4 divisors (see below), whose sum is σ = 16368165888. Its totient is φ = 13640138220.

The previous prime is 15004152049. The next prime is 15004152083. The reversal of 15004152053 is 35025140051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35025140051 = 11 ⋅3184103641.

It is a cyclic number.

It is not a de Polignac number, because 15004152053 - 2² = 15004152049 is a prime.

It is a super-2 number, since 2×15004152053² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15004152013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 682006901 + ... + 682006922.

It is an arithmetic number, because the mean of its divisors is an integer number (4092041472).

Almost surely, 2^15004152053 is an apocalyptic number.

It is an amenable number.

15004152053 is a deficient number, since it is larger than the sum of its proper divisors (1364013835).

15004152053 is a wasteful number, since it uses less digits than its factorization.

15004152053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1364013834.

The product of its (nonzero) digits is 3000, while the sum is 26.

The spelling of 15004152053 in words is "fifteen billion, four million, one hundred fifty-two thousand, fifty-three".