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15005132141 = 35531422311
BaseRepresentation
bin11011111100110000…
…00010010101101101
31102201201210200122212
431332120002111231
5221212303212031
610520540020205
71040561342636
oct157630022555
942651720585
1015005132141
11640000795a
122aa9231665
13155192501c
14a24b9c88d
155cc4ca12b
hex37e60256d

15005132141 has 4 divisors (see below), whose sum is σ = 15005589984. Its totient is φ = 15004674300.

The previous prime is 15005132137. The next prime is 15005132159. The reversal of 15005132141 is 14123150051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14123150051 = 24007588293.

It is a cyclic number.

It is not a de Polignac number, because 15005132141 - 22 = 15005132137 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15005132101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175625 + ... + 246686.

It is an arithmetic number, because the mean of its divisors is an integer number (3751397496).

Almost surely, 215005132141 is an apocalyptic number.

It is an amenable number.

15005132141 is a deficient number, since it is larger than the sum of its proper divisors (457843).

15005132141 is an equidigital number, since it uses as much as digits as its factorization.

15005132141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 457842.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 15005132141 its reverse (14123150051), we get a palindrome (29128282192).

The spelling of 15005132141 in words is "fifteen billion, five million, one hundred thirty-two thousand, one hundred forty-one".

Divisors: 1 35531 422311 15005132141