Base | Representation |
---|---|
bin | 100010000111100011110001… |
… | …110110010100111000010111 |
3 | 201200021221010000012010001022 |
4 | 202013203301312110320113 |
5 | 124131432103430102130 |
6 | 1251045225044151355 |
7 | 43414655042636525 |
oct | 4207436166247027 |
9 | 650257100163038 |
10 | 150053035003415 |
11 | 438a21534262a5 |
12 | 149b534999855b |
13 | 6595c2c32763b |
14 | 290a869c65315 |
15 | 125335547e7e5 |
hex | 8878f1d94e17 |
150053035003415 has 4 divisors (see below), whose sum is σ = 180063642004104. Its totient is φ = 120042428002728.
The previous prime is 150053035003409. The next prime is 150053035003447. The reversal of 150053035003415 is 514300530350051.
150053035003415 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 150053035003415 - 210 = 150053035002391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15005303500337 + ... + 15005303500346.
It is an arithmetic number, because the mean of its divisors is an integer number (45015910501026).
Almost surely, 2150053035003415 is an apocalyptic number.
150053035003415 is a deficient number, since it is larger than the sum of its proper divisors (30010607000689).
150053035003415 is an equidigital number, since it uses as much as digits as its factorization.
150053035003415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30010607000688.
The product of its (nonzero) digits is 67500, while the sum is 35.
Adding to 150053035003415 its reverse (514300530350051), we get a palindrome (664353565353466).
The spelling of 150053035003415 in words is "one hundred fifty trillion, fifty-three billion, thirty-five million, three thousand, four hundred fifteen".
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