Base | Representation |
---|---|
bin | 100010000111100111001001… |
… | …111111000010100111001111 |
3 | 201200022021110201110021201101 |
4 | 202013213021333002213033 |
5 | 124132012020224312133 |
6 | 1251051024541323531 |
7 | 43415143643546635 |
oct | 4207471177024717 |
9 | 650267421407641 |
10 | 150056661166543 |
11 | 438a374429432a |
12 | 149b5ba02665a7 |
13 | 65963896681b1 |
14 | 290aad16a5355 |
15 | 12534b89ad37d |
hex | 8879c9fc29cf |
150056661166543 has 2 divisors, whose sum is σ = 150056661166544. Its totient is φ = 150056661166542.
The previous prime is 150056661166541. The next prime is 150056661166613. The reversal of 150056661166543 is 345661166650051.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150056661166543 - 21 = 150056661166541 is a prime.
Together with 150056661166541, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150056661166541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75028330583271 + 75028330583272.
It is an arithmetic number, because the mean of its divisors is an integer number (75028330583272).
Almost surely, 2150056661166543 is an apocalyptic number.
150056661166543 is a deficient number, since it is larger than the sum of its proper divisors (1).
150056661166543 is an equidigital number, since it uses as much as digits as its factorization.
150056661166543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664000, while the sum is 55.
The spelling of 150056661166543 in words is "one hundred fifty trillion, fifty-six billion, six hundred sixty-one million, one hundred sixty-six thousand, five hundred forty-three".
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