150120413 has 2 divisors, whose sum is σ = 150120414. Its totient is φ = 150120412.

The previous prime is 150120409. The next prime is 150120431. The reversal of 150120413 is 314021051.

Together with next prime (150120431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 149279524 + 840889 = 12218^2 + 917^2 .

It is an emirp because it is prime and its reverse (314021051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 150120413 - 2² = 150120409 is a prime.

It is a super-2 number, since 2×150120413² = 45072276798581138, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 150120391 and 150120400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150120403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75060206 + 75060207.

It is an arithmetic number, because the mean of its divisors is an integer number (75060207).

Almost surely, 2^150120413 is an apocalyptic number.

It is an amenable number.

150120413 is a deficient number, since it is larger than the sum of its proper divisors (1).

150120413 is an equidigital number, since it uses as much as digits as its factorization.

150120413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 150120413 is about 12252.3635678999. The cubic root of 150120413 is about 531.4714220158.

Adding to 150120413 its reverse (314021051), we get a palindrome (464141464).

The spelling of 150120413 in words is "one hundred fifty million, one hundred twenty thousand, four hundred thirteen".