Base | Representation |
---|---|
bin | 100010001011010110010001… |
… | …011111110101100001110111 |
3 | 201201012211012002111121201111 |
4 | 202023112101133311201313 |
5 | 124200213331321001101 |
6 | 1251405010012135451 |
7 | 43442533314433414 |
oct | 4213262137654167 |
9 | 651184162447644 |
10 | 150313411500151 |
11 | 43992618147089 |
12 | 14a378b5467587 |
13 | 65b46560a6413 |
14 | 29192ca80310b |
15 | 1259ee4226251 |
hex | 88b5917f5877 |
150313411500151 has 2 divisors, whose sum is σ = 150313411500152. Its totient is φ = 150313411500150.
The previous prime is 150313411500127. The next prime is 150313411500163. The reversal of 150313411500151 is 151005114313051.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150313411500151 - 219 = 150313410975863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150313411500101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75156705750075 + 75156705750076.
It is an arithmetic number, because the mean of its divisors is an integer number (75156705750076).
Almost surely, 2150313411500151 is an apocalyptic number.
150313411500151 is a deficient number, since it is larger than the sum of its proper divisors (1).
150313411500151 is an equidigital number, since it uses as much as digits as its factorization.
150313411500151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 31.
The spelling of 150313411500151 in words is "one hundred fifty trillion, three hundred thirteen billion, four hundred eleven million, five hundred thousand, one hundred fifty-one".
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