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150402225353351 is a prime number
BaseRepresentation
bin100010001100101000111111…
…001101110011001010000111
3201201112022102200102211022212
4202030220333031303022013
5124203142224142301401
61251513454541214035
743452126231640136
oct4214507715631207
9651468380384285
10150402225353351
1143a17253263564
1214a50b60b6131b
1365bcb3b24488a
14291d713d7991d
15125c4913a1dbb
hex88ca3f373287

150402225353351 has 2 divisors, whose sum is σ = 150402225353352. Its totient is φ = 150402225353350.

The previous prime is 150402225353329. The next prime is 150402225353353. The reversal of 150402225353351 is 153353522204051.

150402225353351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150402225353351 is a prime.

Together with 150402225353353, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 150402225353299 and 150402225353308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150402225353353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75201112676675 + 75201112676676.

It is an arithmetic number, because the mean of its divisors is an integer number (75201112676676).

Almost surely, 2150402225353351 is an apocalyptic number.

150402225353351 is a deficient number, since it is larger than the sum of its proper divisors (1).

150402225353351 is an equidigital number, since it uses as much as digits as its factorization.

150402225353351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 150402225353351 in words is "one hundred fifty trillion, four hundred two billion, two hundred twenty-five million, three hundred fifty-three thousand, three hundred fifty-one".