Base | Representation |
---|---|
bin | 10101111000110000000… |
… | …001101110101001111101 |
3 | 12022210012102201112110211 |
4 | 111320300001232221331 |
5 | 144120240321010323 |
6 | 3110540505232421 |
7 | 213443422503121 |
oct | 25706001565175 |
9 | 5283172645424 |
10 | 1504044313213 |
11 | 52a952893802 |
12 | 2035b1492711 |
13 | abaa5281b50 |
14 | 52b20837581 |
15 | 291cc47470d |
hex | 15e3006ea7d |
1504044313213 has 32 divisors (see below), whose sum is σ = 1633006771200. Its totient is φ = 1377036460800.
The previous prime is 1504044313193. The next prime is 1504044313237. The reversal of 1504044313213 is 3123134404051.
It is not a de Polignac number, because 1504044313213 - 225 = 1504010758781 is a prime.
It is a super-2 number, since 2×15040443132132 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1504044313813) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1650981228 + ... + 1650982138.
It is an arithmetic number, because the mean of its divisors is an integer number (51031461600).
Almost surely, 21504044313213 is an apocalyptic number.
1504044313213 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1504044313213 is a deficient number, since it is larger than the sum of its proper divisors (128962457987).
1504044313213 is a wasteful number, since it uses less digits than its factorization.
1504044313213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2653.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1504044313213 its reverse (3123134404051), we get a palindrome (4627178717264).
The spelling of 1504044313213 in words is "one trillion, five hundred four billion, forty-four million, three hundred thirteen thousand, two hundred thirteen".
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