Base | Representation |
---|---|
bin | 11100000000111110… |
… | …01001100001100011 |
3 | 1102211012110011012212 |
4 | 32000133021201203 |
5 | 221300340113021 |
6 | 10524243112335 |
7 | 1041501400643 |
oct | 160037114143 |
9 | 42735404185 |
10 | 15040551011 |
11 | 6418aa9652 |
12 | 2ab90726ab |
13 | 1559076635 |
14 | a2977c523 |
15 | 5d067485b |
hex | 3807c9863 |
15040551011 has 2 divisors, whose sum is σ = 15040551012. Its totient is φ = 15040551010.
The previous prime is 15040550969. The next prime is 15040551013. The reversal of 15040551011 is 11015504051.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15040551011 is a prime.
Together with 15040551013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (15040551013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7520275505 + 7520275506.
It is an arithmetic number, because the mean of its divisors is an integer number (7520275506).
Almost surely, 215040551011 is an apocalyptic number.
15040551011 is a deficient number, since it is larger than the sum of its proper divisors (1).
15040551011 is an equidigital number, since it uses as much as digits as its factorization.
15040551011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 500, while the sum is 23.
The spelling of 15040551011 in words is "fifteen billion, forty million, five hundred fifty-one thousand, eleven".
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