Base | Representation |
---|---|
bin | 11100000001000001… |
… | …11010010110001101 |
3 | 1102211020022122010111 |
4 | 32000200322112031 |
5 | 221300444410013 |
6 | 10524301040021 |
7 | 1041505334146 |
oct | 160040722615 |
9 | 42736278114 |
10 | 15041013133 |
11 | 6419294873 |
12 | 2ab9256011 |
13 | 15591a8a93 |
14 | a2985cacd |
15 | 5d071673d |
hex | 38083a58d |
15041013133 has 2 divisors, whose sum is σ = 15041013134. Its totient is φ = 15041013132.
The previous prime is 15041013131. The next prime is 15041013137. The reversal of 15041013133 is 33131014051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9216576009 + 5824437124 = 96003^2 + 76318^2 .
It is a cyclic number.
It is not a de Polignac number, because 15041013133 - 21 = 15041013131 is a prime.
Together with 15041013131, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15041013131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7520506566 + 7520506567.
It is an arithmetic number, because the mean of its divisors is an integer number (7520506567).
Almost surely, 215041013133 is an apocalyptic number.
It is an amenable number.
15041013133 is a deficient number, since it is larger than the sum of its proper divisors (1).
15041013133 is an equidigital number, since it uses as much as digits as its factorization.
15041013133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 15041013133 its reverse (33131014051), we get a palindrome (48172027184).
The spelling of 15041013133 in words is "fifteen billion, forty-one million, thirteen thousand, one hundred thirty-three".
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