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15042551309 is a prime number
BaseRepresentation
bin11100000001001101…
…10001111000001101
31102211100012210002222
432000212301320031
5221301343120214
610524354025125
71041524401502
oct160046617015
942740183088
1015042551309
11641a145495
122ab98781a5
1315595c6c46
14a29b3d4a9
155d091c38e
hex3809b1e0d

15042551309 has 2 divisors, whose sum is σ = 15042551310. Its totient is φ = 15042551308.

The previous prime is 15042551281. The next prime is 15042551327. The reversal of 15042551309 is 90315524051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8119812100 + 6922739209 = 90110^2 + 83203^2 .

It is an emirp because it is prime and its reverse (90315524051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15042551309 - 212 = 15042547213 is a prime.

It is a super-2 number, since 2×150425513092 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15042551339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7521275654 + 7521275655.

It is an arithmetic number, because the mean of its divisors is an integer number (7521275655).

Almost surely, 215042551309 is an apocalyptic number.

It is an amenable number.

15042551309 is a deficient number, since it is larger than the sum of its proper divisors (1).

15042551309 is an equidigital number, since it uses as much as digits as its factorization.

15042551309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 35.

The spelling of 15042551309 in words is "fifteen billion, forty-two million, five hundred fifty-one thousand, three hundred nine".