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15043241041 is a prime number
BaseRepresentation
bin11100000001010010…
…11010010001010001
31102211101111211020121
432000221122101101
5221302032203131
610524420510241
71041533303413
oct160051322121
942741454217
1015043241041
11641a576714
122ab9b4b381
1315597a8b7a
14a29c7c9b3
155d0a06911
hex380a5a451

15043241041 has 2 divisors, whose sum is σ = 15043241042. Its totient is φ = 15043241040.

The previous prime is 15043241039. The next prime is 15043241047. The reversal of 15043241041 is 14014234051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13063347025 + 1979894016 = 114295^2 + 44496^2 .

It is an emirp because it is prime and its reverse (14014234051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15043241041 - 21 = 15043241039 is a prime.

Together with 15043241039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 15043240997 and 15043241015.

It is not a weakly prime, because it can be changed into another prime (15043241047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7521620520 + 7521620521.

It is an arithmetic number, because the mean of its divisors is an integer number (7521620521).

Almost surely, 215043241041 is an apocalyptic number.

It is an amenable number.

15043241041 is a deficient number, since it is larger than the sum of its proper divisors (1).

15043241041 is an equidigital number, since it uses as much as digits as its factorization.

15043241041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 15043241041 its reverse (14014234051), we get a palindrome (29057475092).

The spelling of 15043241041 in words is "fifteen billion, forty-three million, two hundred forty-one thousand, forty-one".