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150555400231 is a prime number
BaseRepresentation
bin1000110000110111001…
…1010001100000100111
3112101121110112202202111
42030031303101200213
54431314140301411
6153055244421451
713606621533625
oct2141563214047
9471543482674
10150555400231
1158939664605
1225218847887
1311274660952
147403448515
153db273c721
hex230dcd1827

150555400231 has 2 divisors, whose sum is σ = 150555400232. Its totient is φ = 150555400230.

The previous prime is 150555400223. The next prime is 150555400243. The reversal of 150555400231 is 132004555051.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 150555400231 - 23 = 150555400223 is a prime.

It is a super-2 number, since 2×1505554002312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150555400193 and 150555400202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150555400201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75277700115 + 75277700116.

It is an arithmetic number, because the mean of its divisors is an integer number (75277700116).

Almost surely, 2150555400231 is an apocalyptic number.

150555400231 is a deficient number, since it is larger than the sum of its proper divisors (1).

150555400231 is an equidigital number, since it uses as much as digits as its factorization.

150555400231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 150555400231 its reverse (132004555051), we get a palindrome (282559955282).

The spelling of 150555400231 in words is "one hundred fifty billion, five hundred fifty-five million, four hundred thousand, two hundred thirty-one".