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150982336751 is a prime number
BaseRepresentation
bin1000110010011100111…
…1111010000011101111
3112102201012220101120012
42030213033322003233
54433202434234001
6153205455243435
713623324454541
oct2144717720357
9472635811505
10150982336751
1159038658304
122531781957b
1311311c439cc
147444021691
153dd9e722bb
hex23273fa0ef

150982336751 has 2 divisors, whose sum is σ = 150982336752. Its totient is φ = 150982336750.

The previous prime is 150982336733. The next prime is 150982336753. The reversal of 150982336751 is 157633289051.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150982336751 is a prime.

It is a super-3 number, since 3×1509823367513 (a number of 35 digits) contains 333 as substring.

Together with 150982336753, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 150982336751.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150982336753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75491168375 + 75491168376.

It is an arithmetic number, because the mean of its divisors is an integer number (75491168376).

Almost surely, 2150982336751 is an apocalyptic number.

150982336751 is a deficient number, since it is larger than the sum of its proper divisors (1).

150982336751 is an equidigital number, since it uses as much as digits as its factorization.

150982336751 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 50.

The spelling of 150982336751 in words is "one hundred fifty billion, nine hundred eighty-two million, three hundred thirty-six thousand, seven hundred fifty-one".