151034004535 has 4 divisors (see below), whose sum is σ = 181240805448. Its totient is φ = 120827203624.

The previous prime is 151034004533. The next prime is 151034004557. The reversal of 151034004535 is 535400430151.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 535400430151 = 15377 ⋅34818263.

It is a cyclic number.

It is not a de Polignac number, because 151034004535 - 2¹ = 151034004533 is a prime.

It is a super-3 number, since 3×151034004535³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 151034004497 and 151034004506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151034004533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15103400449 + ... + 15103400458.

It is an arithmetic number, because the mean of its divisors is an integer number (45310201362).

Almost surely, 2^151034004535 is an apocalyptic number.

151034004535 is a deficient number, since it is larger than the sum of its proper divisors (30206800913).

151034004535 is an equidigital number, since it uses as much as digits as its factorization.

151034004535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30206800912.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 151034004535 its reverse (535400430151), we get a palindrome (686434434686).

The spelling of 151034004535 in words is "one hundred fifty-one billion, thirty-four million, four thousand, five hundred thirty-five".