Base | Representation |
---|---|
bin | 11100001000100011… |
… | …01011110001001111 |
3 | 1102222122002022100221 |
4 | 32010101223301033 |
5 | 221413124131002 |
6 | 10534433532211 |
7 | 1043202662542 |
oct | 160421536117 |
9 | 42878068327 |
10 | 15104130127 |
11 | 6450984579 |
12 | 2b16414067 |
13 | 15692a7708 |
14 | a33dac859 |
15 | 5d6032c37 |
hex | 38446bc4f |
15104130127 has 2 divisors, whose sum is σ = 15104130128. Its totient is φ = 15104130126.
The previous prime is 15104130091. The next prime is 15104130187. The reversal of 15104130127 is 72103140151.
15104130127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15104130127 is a prime.
It is a super-2 number, since 2×151041301272 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15104130187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7552065063 + 7552065064.
It is an arithmetic number, because the mean of its divisors is an integer number (7552065064).
Almost surely, 215104130127 is an apocalyptic number.
15104130127 is a deficient number, since it is larger than the sum of its proper divisors (1).
15104130127 is an equidigital number, since it uses as much as digits as its factorization.
15104130127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 15104130127 its reverse (72103140151), we get a palindrome (87207270278).
The spelling of 15104130127 in words is "fifteen billion, one hundred four million, one hundred thirty thousand, one hundred twenty-seven".
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