15105105131 has 2 divisors, whose sum is σ = 15105105132. Its totient is φ = 15105105130.

The previous prime is 15105105091. The next prime is 15105105133. The reversal of 15105105131 is 13150150151.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15105105131 - 2¹⁰ = 15105104107 is a prime.

It is a super-2 number, since 2×15105105131² (a number of 21 digits) contains 22 as substring.

Together with 15105105133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 15105105097 and 15105105106.

It is not a weakly prime, because it can be changed into another prime (15105105133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7552552565 + 7552552566.

It is an arithmetic number, because the mean of its divisors is an integer number (7552552566).

Almost surely, 2^15105105131 is an apocalyptic number.

15105105131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15105105131 is an equidigital number, since it uses as much as digits as its factorization.

15105105131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 375, while the sum is 23.

Adding to 15105105131 its reverse (13150150151), we get a palindrome (28255255282).

The spelling of 15105105131 in words is "fifteen billion, one hundred five million, one hundred five thousand, one hundred thirty-one".