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151113245042 = 275556622521
BaseRepresentation
bin1000110010111100001…
…1010010000101110010
3112110001100020012222102
42030233003102011302
54433434442320132
6153230453140402
713626504250424
oct2145703220562
9473040205872
10151113245042
11590a553a681
122535362a702
13113330b9a36
14745757a814
153de66cec62
hex232f0d2172

151113245042 has 4 divisors (see below), whose sum is σ = 226669867566. Its totient is φ = 75556622520.

The previous prime is 151113245039. The next prime is 151113245071. The reversal of 151113245042 is 240542311151.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 83024083321 + 68089161721 = 288139^2 + 260939^2 .

It is a junction number, because it is equal to n+sod(n) for n = 151113244996 and 151113245014.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37778311259 + ... + 37778311262.

Almost surely, 2151113245042 is an apocalyptic number.

151113245042 is a deficient number, since it is larger than the sum of its proper divisors (75556622524).

151113245042 is an equidigital number, since it uses as much as digits as its factorization.

151113245042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75556622523.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 151113245042 its reverse (240542311151), we get a palindrome (391655556193).

The spelling of 151113245042 in words is "one hundred fifty-one billion, one hundred thirteen million, two hundred forty-five thousand, forty-two".

Divisors: 1 2 75556622521 151113245042