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15112013 = 72158859
BaseRepresentation
bin111001101001…
…011101001101
31001102202210012
4321221131031
512332041023
61255523005
7242310230
oct71513515
931382705
1015112013
118591974
125089465
133191627
142015417
1514d7978
hexe6974d

15112013 has 4 divisors (see below), whose sum is σ = 17270880. Its totient is φ = 12953148.

The previous prime is 15112007. The next prime is 15112033. The reversal of 15112013 is 31021151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15112013 is a prime.

It is a super-3 number, since 3×151120133 (a number of 23 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15112003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1079423 + ... + 1079436.

It is an arithmetic number, because the mean of its divisors is an integer number (4317720).

Almost surely, 215112013 is an apocalyptic number.

It is an amenable number.

15112013 is a deficient number, since it is larger than the sum of its proper divisors (2158867).

15112013 is an equidigital number, since it uses as much as digits as its factorization.

15112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2158866.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 15112013 is about 3887.4172660007. The cubic root of 15112013 is about 247.2335697036.

Adding to 15112013 its reverse (31021151), we get a palindrome (46133164).

The spelling of 15112013 in words is "fifteen million, one hundred twelve thousand, thirteen".

Divisors: 1 7 2158859 15112013