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151124117 is a prime number
BaseRepresentation
bin10010000000111…
…11100010010101
3101112100220022112
421000133202111
5302141432432
622555040405
73513351044
oct1100374225
9345326275
10151124117
117833a871
1242740105
1325403771
14160dc55b
15d4027b2
hex901f895

151124117 has 2 divisors, whose sum is σ = 151124118. Its totient is φ = 151124116.

The previous prime is 151124107. The next prime is 151124123. The reversal of 151124117 is 711421151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 148693636 + 2430481 = 12194^2 + 1559^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-151124117 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 151124092 and 151124101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (151124107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75562058 + 75562059.

It is an arithmetic number, because the mean of its divisors is an integer number (75562059).

Almost surely, 2151124117 is an apocalyptic number.

It is an amenable number.

151124117 is a deficient number, since it is larger than the sum of its proper divisors (1).

151124117 is an equidigital number, since it uses as much as digits as its factorization.

151124117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 280, while the sum is 23.

The square root of 151124117 is about 12293.2549391933. The cubic root of 151124117 is about 532.6532633551.

Adding to 151124117 its reverse (711421151), we get a palindrome (862545268).

The spelling of 151124117 in words is "one hundred fifty-one million, one hundred twenty-four thousand, one hundred seventeen".